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RAJASTHAN PMT Rajasthan - PMT Solved Paper-1999

  • question_answer
    \[N{{O}_{2}}+\frac{1}{2}{{O}_{2}}N{{O}_{3}}...........{{K}_{1}}\] \[2N{{O}_{2}}+{{O}_{2}}2N{{O}_{3}}...........{{K}_{2}}\] For the above reaction the relation between equilibrium constant is:

    A)  \[{{K}_{2}}={{({{K}_{1}})}^{2}}\]

    B)                         \[{{K}_{2}}=\frac{1}{{{K}_{1}}}\]

    C)                         \[{{K}_{2}}=\frac{1}{{{K}_{{{1}^{2}}}}}\]

    D)                         \[{{K}_{1}}={{K}_{2}}\]                                 

    Correct Answer: C

    Solution :

    \[{{K}_{1}}=\frac{[N{{O}_{3}}]}{[N{{O}_{2}}]{{[{{O}_{2}}]}^{1/2}}}\] \[{{K}_{2}}=\frac{{{[N{{O}_{3}}]}^{2}}}{{{[N{{O}_{2}}]}^{2}}[{{O}_{2}}]}\] So,          \[{{K}_{2}}={{({{K}_{1}})}^{2}}\]


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