RAJASTHAN PMT Rajasthan - PMT Solved Paper-1999

  • question_answer
    \[CHC\equiv CH\xrightarrow[Ni]{{{H}_{2}}}A,\] product A is:

    A)  \[C{{H}_{2}}=C{{H}_{2}}\]

    B)                         \[C{{H}_{4}}\]

    C)                          \[C{{H}_{3}}-C{{H}_{3}}\]

    D)                         \[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{3}}\]

    Correct Answer: A

    Solution :

    \[\underset{Acetylene}{\mathop{CH\equiv CH}}\,\xrightarrow[Ni]{{{H}_{2}}}C{{H}_{2}}=C{{H}_{2}}\]


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