A) Fructose \[+{{H}_{2}}O\]
B) \[C{{O}_{2}}+{{H}_{2}}O\]
C) Glucose \[+{{H}_{2}}O\]
D) Alcohol \[+C{{O}_{2}}\]
Correct Answer: D
Solution :
\[\underset{Glu\cos e}{\mathop{{{C}_{6}}{{H}_{12}}{{O}_{6}}}}\,\xrightarrow[respiration]{anaerobic}\underset{Ethyle\,alcohol}{\mathop{\,2{{C}_{2}}{{H}_{5}}OH+2C{{O}_{2}}}}\,\] + 28 kcal energy
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