RAJASTHAN PMT Rajasthan - PMT Solved Paper-1999

  • question_answer
    If temperature of an object is \[140{}^\circ F\], then its temperature in centrigrade is:

    A) \[105{}^\circ C\]              

    B)        \[32{}^\circ C\]

    C) \[140{}^\circ C\]              

    D)        \[60{}^\circ C\]

    Correct Answer: D

    Solution :

    Relation between centigrade and Fahrenheit scale. \[\frac{C}{5}=\frac{F-32}{9}\] \[\begin{align}   & \frac{C}{5}=\frac{140-32}{9} \\  & C={{60}^{o}} \\ \end{align}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner