A) 100 V
B) 200 V
C) 156 V
D) \[100\times {{2}^{-2/3}}V\]
Correct Answer: C
Solution :
Volume of large drop \[=2\times \] volume of smaller drop \[\frac{4}{3}\pi {{R}^{3}}=2\times \frac{4}{3}\pi {{r}^{3}}\] \[R={{2}^{1/3}}^{\,\,r}\] Potential of small drop\[V=\frac{Kq}{r}=100\] volt Potential of large drop \[V=\frac{Kq}{R}\] \[V=\frac{k2q}{{{2}^{1/3}}\,r}={{2}^{2/3}}\left( \frac{kq}{r} \right)\] \[{{2}^{2/3}}\times 100=156\,\,\,\text{V}\]
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