A) \[+6\]
B) \[-6\]
C) \[+4\]
D) \[-4\]
Correct Answer: A
Solution :
In \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\] the oxidation number of \[Cr\] \[2+2x+(-2\times 7)=0\] \[2+2x-14=0\] \[2x-12=0\] \[x=6\]You need to login to perform this action.
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