A) \[{{K}_{2}}={{K}_{1}}^{2}\]
B) \[{{K}_{2}}=\frac{1}{{{K}_{{{1}^{2}}}}}\]
C) \[{{K}_{2}}={{K}_{1}}\]
D) \[{{K}_{2}}=\frac{1}{{{K}_{1}}}\]
Correct Answer: A
Solution :
\[S{{O}_{2}}+\frac{1}{2}{{O}_{2}}S{{O}_{3}}\] \[{{K}_{1}}=\frac{[S{{O}_{3}}]}{[S{{O}_{2}}]{{[{{O}_{2}}]}^{1/2}}}\] \[2S{{O}_{2}}+{{O}_{2}}2S{{O}_{3}}\] \[{{K}_{2}}=\frac{{{[S{{O}_{3}}]}^{2}}}{{{[S{{O}_{2}}]}^{2}}[{{O}_{2}}]}\] So that \[{{K}_{2}}={{K}_{1}}^{2}\]
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