A) \[1.20\times {{10}^{-10}}\]
B) \[1.36\times {{10}^{-4}}\]
C) \[2.60\times {{10}^{-7}}\]
D) \[2.46\times {{10}^{14}}\]
Correct Answer: B
Solution :
\[A{{X}_{2}}{{A}^{2+}}+2{{X}^{-}}\] \[{{K}_{sp}}=(s)\,{{(2s)}^{2}}=4{{s}^{3}}\] \[s={{\left( \frac{{{K}_{sp}}}{4} \right)}^{1/3}}\] \[={{\left( \frac{1.0\times {{10}^{-11}}}{4} \right)}^{1/3}}\]
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