RAJASTHAN PMT Rajasthan - PMT Solved Paper-2000

  • question_answer
    A current of 1 mA is flowing in conductor, then number of electrons passing through per second in conductor is:

    A)  \[6.25\times {{10}^{17}}\]          

    B)         \[6.25\times {{10}^{15}}\]

    C)  \[1.6\,\times {{10}^{16}}\]         

    D)         \[1.6\,\times {{10}^{-16}}\]

    Correct Answer: B

    Solution :

        \[q=it\] \[ne=it\,\Rightarrow n=\frac{it}{e}\] \[=\frac{1\times {{10}^{-3}}\times 1}{1.6\times {{10}^{-19}}}=6.25\times {{10}^{15}}\]


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