RAJASTHAN PMT Rajasthan - PMT Solved Paper-2000

  • question_answer
    The energy of an electron in the excited state of H-atom is - 1.5 eV, then according to Bohrs model, its momentum will be:

    A)  \[3.15\times {{10}^{-34}}\,J-\sec \]

    B)  \[1.82\times {{10}^{-34}}\,J-\sec \]

    C)  \[5.01\times {{10}^{-30}}\,J-\sec \]

    D)         \[7.14\times {{10}^{-31}}\,J-\sec \]

    Correct Answer: A

    Solution :

    \[\begin{align}   & \left( {{n}^{2}}=\frac{13.6}{1.5}\Rightarrow {{n}^{2}}=9 \right) \\  & \therefore n=3 \\  & \text{for}\,\text{1}\text{.5}\,\text{eV,}\,\text{n=3} \\ \end{align}\] Angular momentum \[=n\frac{h}{\pi }\] \[=\frac{3\times 6.6\times {{10}^{10-34}}}{2\times 3.14}=3.15\times {{10}^{-34}}\,\text{J-sec}\]


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