RAJASTHAN PMT Rajasthan - PMT Solved Paper-2000

  • question_answer
    A particle is moving with constant speed in horizontal circle of radius R. Then in completing half cycle:

    A)  change in momentum is \[m\upsilon r\]

    B)  change in kinetic energy is\[\frac{1}{2}m\upsilon r\]

    C)  change in kinetic energy is \[m{{\upsilon }^{2}}\]

    D)  change in kinetic energy is zero

    Correct Answer: D

    Solution :

    Speed of particle is constant, so its kinetic energy will also be constant. Therefore change in kinetic energy will be zero.


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