A) a
B) \[\sqrt{2}\,a\]
C) \[2\,a\]
D) \[\sqrt{3}\,a\]
Correct Answer: D
Solution :
\[{{y}_{1}}=a\,\sin \,(\omega t+\pi /3)\] \[{{y}_{2}}=a\,\sin \,\omega t\] Comparing these equations with \[\begin{align} & {{y}_{2}}=a\,\sin \,(\omega t\,\text{)} \\ & {{a}_{1}}-{{a}_{2}}=a,\text{=}\pi \text{/3} \\ \end{align}\] Resultant amplitude \[R=\sqrt{{{a}_{1}}^{2}+a_{2}^{2}+2{{a}_{1}}a{{ & }_{2}}\cos \,}\] \[=\sqrt{{{a}^{2}}+{{a}^{2}}+2{{a}^{2}}\cos \,\frac{\pi }{3}}\] \[=\sqrt{3}a\]You need to login to perform this action.
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