A) \[{{[C{{r}_{2}}{{O}_{7}}]}^{-2}}\xrightarrow{{}}{{[Cr{{O}_{4}}]}^{-2}}\]
B) \[{{[Fe{{(CN)}_{6}}]}^{-4}}\xrightarrow{{}}{{[Fe{{(CN)}_{6}}]}^{-3}}\]
C) \[Mn{{O}_{4}}^{-}\xrightarrow{{}}Mn{{O}_{2}}\]
D) \[Mn{{O}_{4}}^{-2}\xrightarrow{{}}Mn{{O}_{4}}^{-1}\]
Correct Answer: C
Solution :
\[Mn{{O}_{4}}^{-}\xrightarrow{{}}Mn{{O}_{2}}\] \[M{{n}^{+7}}\xrightarrow{{}}M{{n}^{+4}}\] In this reaction \[M{{n}^{+7}}\] reductive by \[M{{n}^{+4}}\] The ore of copper is malechite \[(CuC{{O}_{3}}.Cu{{(OH)}_{2}}\].
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