RAJASTHAN PMT Rajasthan - PMT Solved Paper-2001

  • question_answer
    The molar solubility for a solid \[[Mg{{(OH)}_{2}}]\]is 5 and solubility product is \[{{K}_{sp}}\] will be:

    A)  \[s\]             

    B)  \[{{s}^{3}}\]

    C)  \[4{{s}^{3}}\]            

    D)  none of these

    Correct Answer: C

    Solution :

    \[\underset{s}{\mathop{Mg{{(OH)}_{2}}}}\,\underset{s}{\mathop{M{{g}^{+}}}}\,+\underset{2s}{\mathop{2O{{H}^{-}}}}\,\] \[{{K}_{sp}}Mg{{(OH)}_{2}}\underset{s}{\mathop{[M{{g}^{+}}]}}\,+\underset{\times {{(2s)}^{2}}}{\mathop{[2O{{H}^{-}}]}}\,\]                 \[{{K}_{sp}}=4{{s}^{3}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner