A) \[0.04-16{}^\circ 79\]
B) \[0.4-20{}^\circ 70\]
C) \[4.0-20{}^\circ 79\]
D) \[4.0-16{}^\circ 79\]
Correct Answer: D
Solution :
The percentage of \[C{{O}_{2}}:{{O}_{2}} & :{{N}_{2}}\,is\,\]4.0: 16 : 79 in exhaled air of man.
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