RAJASTHAN PMT Rajasthan - PMT Solved Paper-2001

  • question_answer
    Two mass of 9 g arid 6 g are tied to a string, which passes over a smooth pulley. Then common acceleration will be:

    A)  \[1.96\text{ }cm/{{s}^{2}}\]                       

    B)  \[\text{48 }cm/{{s}^{2}}\]

    C)  \[\text{98 }cm/{{s}^{2}}\]          

    D)         \[\text{196 }cm/{{s}^{2}}\]

    Correct Answer: D

    Solution :

    Common acceleration\[\begin{align}   & =\frac{{{m}_{1}}-{{m}_{2}}}{{{m}_{1}}+{{m}_{2}}}\times g \\  & =196\,cm/{{s}^{2}} \\ \end{align}\]


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