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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2001

  • question_answer
    Velocity of a sound wave is 360 m/s and frequency is 50 Hz, then path difference will be at the phase difference of \[60{}^\circ \] is:

    A)  10 cm                  

    B)         1.2 cm

    C)  15 cm                  

    D)         100 cm

    Correct Answer: B

    Solution :

    Phase difference\[\frac{2\pi }{\lambda }\times \]path difference \[\begin{align}   & \frac{2\pi }{3}=\frac{2\pi }{7.2}\times \Delta A\,\left\{ \lambda =\frac{\upsilon }{n}=\frac{360}{50}=7.2\,m \right\} \\  & \Delta A=1.2\,cm \\ \end{align}\]


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