RAJASTHAN PMT Rajasthan - PMT Solved Paper-2001

  • question_answer
    Mass of hydrogen-atom is \[1.7\times {{10}^{-27}}\] kg and inter atomic distance is \[4\times {{10}^{-10}}\,m\]. Then moment of inertia of H2 molecules with respect to its centre of mass:

    A)  \[7.6\,\times {{10}^{-43}}\,k{{g}^{-}}{{m}^{2}}\]

    B)            \[7.6\,\times {{10}^{-47}}\,k{{g}^{-}}{{m}^{2}}\]

    C)  \[6.7\,\times {{10}^{-47}}\,k{{g}^{-}}{{m}^{2}}\]                      

    D)  \[13.6\,\times {{10}^{-47}}\,k{{g}^{-}}{{m}^{2}}\]

    Correct Answer: D

    Solution :

    Moment of inertia \[I=\frac{1}{2}m{{r}^{2}}\]    \[\begin{align}   & =\frac{1}{2}\times 1.7\times {{10}^{-27}}\times 16\times {{10}^{20}} \\  & =13.6\times {{10}^{-47}}\,\text{kg}\text{.}{{\text{m}}^{\text{2}}}^{.} \\ \end{align}\]


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