A) 4 : 9
B) 9 : 4
C) 8 : 27
D) 1 : 1
Correct Answer: A
Solution :
According to rule for flowing of liquid. product of area and velocity is same \[{{A}_{1}}{{\upsilon }_{1}}={{A}_{2}}{{\upsilon }_{2}}\] \[\frac{{{\upsilon }_{1}}}{{{\upsilon }_{2}}}=\frac{{{A}_{2}}}{{{A}_{1}}}\] \[=\frac{\pi {{r}_{2}}^{2}}{\pi {{r}_{1}}^{2}}={{\left( \frac{{{r}_{2}}}{{{r}_{1}}} \right)}^{2}}=\frac{4}{9}=4:9\]
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