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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2001

  • question_answer
    In this reaction \[X+2YU+3V\] chemically known that \[10g\]of X react with \[20g\]of mixture of Y gives \[5g\]of U. Then quantity of V will be:

    A)  \[30g\]                

    B)  \[25g\]

    C)  \[2.5g\]          

    D)  none of these

    Correct Answer: B

    Solution :

    \[X+2YU+3V\] \[\frac{-d[X]}{dt}=\frac{-d[Y]}{2dt}=\frac{d(U)}{dt}=\frac{d[V]}{3dt}\] \[[X]=10g\frac{d[1]}{dt}=\frac{d[V]}{3dt}\] \[[Y]=20g\] \[[U]=5g\frac{d[5]}{dt}=d\frac{[V]}{3dt}\] \[[V]=25g\]


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