A) \[1\times {{10}^{-7}}\]
B) \[3.2\times {{10}^{-2}}\]
C) \[1\times {{10}^{-5}}\]
D) \[3.2\times {{10}^{-5}}\]
Correct Answer: D
Solution :
Given, solubility of \[PbC{{l}_{2}}(s)=2\times {{10}^{-2}}mol/litre\] \[PbC{{l}_{2}}Pb+2C{{l}^{-}}\] \[{{K}_{sp}}=[s]\,{{[2s]}^{2}}\] \[=4{{s}^{3}}\] \[=4\times {{(2\times {{10}^{-2}})}^{3}}\] \[=32\times {{10}^{-6}}\] \[{{K}_{sp}}=3.2\times {{10}^{-5}}\]
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