A) \[[Ar]\,4{{s}^{2}}\,3{{d}^{6}}\]
B) \[[Ar]\,\,3{{d}^{6}}\]
C) \[[Ar]\,\,4{{s}^{2}}3{{d}^{4}}\]
D) \[[Ar]\,\,4{{s}^{2}}3{{d}^{0}}\]
Correct Answer: B
Solution :
\[Fe\](atomic number \[=26\]) \[=1{{s}^{2}},2{{s}^{2}}\text{ }2{{p}^{6}},3{{s}^{2}}\text{ }3{{p}^{6}}\text{ }3{{d}^{6}},4{{s}^{2}}\] \[F{{e}^{+2}}=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{6}}\] \[=[Ar]3{{d}^{6}}\]
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