RAJASTHAN PMT Rajasthan - PMT Solved Paper-2002

  • question_answer
    Surface tension of liquid is 5N/m. If a thin film of area 0.02 m2 is made in a ring then the surface energy will be :

    A)  \[\text{5 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-3}\,}}\text{J}\]        

    B)         \[\text{2}\text{.5 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-3}\,}}\text{J}\]

    C)  \[\text{1 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-1}\,}}\text{J}\]       

    D)         \[\text{5 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-1}\,}}\text{J}\]

    Correct Answer: C

    Solution :

                                Surface energy\[=T.A\]          \[\begin{align}   & =5\times 0.02=0.1 \\  & =1\times {{10}^{-1}}\,\text{J} \\ \end{align}\]


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