A) 1-bromo butane
B) 1-bromo-2-methyl propane
C) 2-bromo butane
D) 2-bromo-2-methyl propane
Correct Answer: D
Solution :
\[\underset{\text{2-methyl propane}}{\mathop{C{{H}_{3}}-\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{C}}\,}}\,=C{{H}_{2}}}}\,+HBr\xrightarrow{{}}\underset{\begin{smallmatrix} \text{2-bromo-2-methyl} \\ \text{propane} \end{smallmatrix}}{\mathop{C{{H}_{3}}-\underset{Br}{\mathop{\underset{|}{\mathop{\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{C}}\,}}\,}}\,}}\,-C{{H}_{3}}}}\,\]
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