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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2002

  • question_answer
    A sound wave of frequency 660 Hz is incident normally at reflecting wall then minimum distance from wall at which particles amplitude will be maximum (velocity of sound = 330 m/s):

    A)  0.215 m                              

    B)  0.125 m

    C)  1 m                       

    D)         0.5 m

    Correct Answer: D

    Solution :

    Wavelength\[\lambda =\frac{\upsilon }{n}\]         \[=\frac{330}{660}=\frac{1}{2}=0.5\,m\] For maximum amplitude, distance should be 0.5 m.


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