RAJASTHAN PMT Rajasthan - PMT Solved Paper-2002

  • question_answer
    Escape velocity for a rocket is 11.2 km/s. If it is taken to a planet where the radius and acceleration due to gravity is double than earth, then escape velocity will be:

    A)  5.6m/s                

    B)         11.2m/s

    C)  22.4 km/s          

    D)         44.2 m/s

    Correct Answer: C

    Solution :

    Escape velocity from earths surface\[{{\upsilon }_{p}}=\sqrt{2{{g}_{p}}{{R}_{p}}}\] Escape velocity from planet \[{{\upsilon }_{p}}\,=\sqrt{2{{g}_{p}}{{R}_{p}}}\]              \[\begin{align}   & =\sqrt{2(2g)(2\operatorname{Re})=2{{\upsilon }_{e}}} \\  & =2\times 11.2=22.4\,km/s \\ \end{align}\]


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