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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2002

  • question_answer
    Two ions\[A:{{Z}_{1}}=24\] and charge = e and B \[:{{Z}_{2}}=22\] and charge = 2e are enter in a transverse uniform magnetic field with same velocity in mass spectrograph then the ratio of their radii are:          

    A)  \[\frac{11}{24}\]                             

    B)         \[\frac{12}{11}\]   

    C)  \[\frac{11}{22}\]                             

    D)         \[\frac{24}{11}\]

    Correct Answer: A

    Solution :

    Radius of charged particle\[r=\frac{m\upsilon }{Bq}\] \[\Rightarrow \]               \[r\propto \frac{m}{q}\]                                 \[\frac{{{r}_{1}}}{{{r}_{2}}}=\frac{{{Z}_{2}}}{{{Z}_{1}}}\frac{e}{2e}\]                                 \[=\frac{22}{24}\times \frac{1}{2}=\frac{11}{24}\]


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