A) Butanol-2
B) Butanol-1
C) 2-methyl ketone
D) 2-methyl propane
Correct Answer: A
Solution :
In haloform reaction, compounds having the structure \[R-\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-C{{H}_{3}}\] or \[R-\underset{O}{\mathop{\underset{\ ||}{\mathop{C}}\,}}\,-C{{H}_{3}}\] are treated with an excess of iodine solution and alkali to produce iodoform. \[\underset{\text{Butanol-2}}{\mathop{\overset{1}{\mathop{C{{H}_{3}}}}\,\underset{OH}{\mathop{\underset{|}{\mathop{\overset{2}{\mathop{C}}\,}}\,}}\,H}}\,-\overset{3}{\mathop{C{{H}_{2}}}}\,-\overset{4}{\mathop{C{{H}_{3}}}}\,+NaOH+\underset{\text{Halogen}}{\mathop{{{X}_{2}}}}\,\to \underset{Haloform}{\mathop{CH{{X}_{3}}}}\,\] Therefore, 2-butanol responds to haloform test.
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