A) \[4.48\text{ }litre\]
B) \[22.4\text{ }litre\]
C) \[2.24\text{ }litre\]
D) None of these
Correct Answer: A
Solution :
The decomposition of \[CaC{{O}_{3}}\] takes place as below \[\underset{100\,gm}{\mathop{CaC{{O}_{3}}}}\,\xrightarrow{{}}\underset{56\,gm}{\mathop{CaO}}\,+\underset{22.4\,lit}{\mathop{C{{O}_{2}}}}\,\] \[\because \] \[100gm\text{ }CaC{{O}_{3}}\]at STP produce \[=22.4\text{ }lit\text{ }C{{O}_{2}}\] \[\therefore \] \[20\text{ }gm\] \[CaC{{O}_{3}}\] at STP produce \[=\frac{22.4}{100}\times 20\] \[=4.48\text{ }lit\text{ }C{{O}_{2}}\]
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