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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2003

  • question_answer
    If volume of 2 moles of an ideal gas at \[540\text{ }K\]is \[44.8\text{ }litre,\]its pressure is

    A)  \[2\text{ }aim.\]                             

    B)         \[4\,atm.\]

    C)         \[5\text{ }aim.\]                             

    D)         \[6\text{ }atm.\]

    Correct Answer: A

    Solution :

    \[\because \]    \[PV=nRT\]                         \[\therefore \]  \[P=\frac{nRT}{V}\] \[P=\frac{2\times 0.082\times 540}{44.8}\left[ \begin{align}   & \because \,\,\,n=2mol \\  & R=0.082 \\  & T=540 \\  & V=44.8 \\ \end{align} \right]\] \[P=2atm\].


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