A) \[C{{H}_{4}}\]
B) \[{{C}_{2}}{{H}_{2}}\]
C) \[{{C}_{2}}{{H}_{4}}\]
D) \[{{C}_{2}}{{H}_{6}}\]
Correct Answer: B
Solution :
When acetylene is passed through an ammoniacal solution of silver nitrate, a white precipitate of silver acetylide is formed: \[HC\equiv CH+2AgN{{O}_{3}}+2N{{H}_{4}}OH\xrightarrow{{}}\] \[\underset{(White\,\,ppt.)}{\mathop{\underset{Silver\,acetylide}{\mathop{AgC\equiv C-Ag}}\,}}\,+2N{{H}_{4}}N{{O}_{3}}+2{{H}_{2}}O\] \[C{{H}_{4}},\] \[{{C}_{2}}{{H}_{4}}\] and \[{{C}_{2}}{{H}_{6}}\] do not react with\[AgN{{O}_{3}}\]. Therefore, \[{{C}_{2}}{{H}_{2}}\] does not come out from Wolf bottle of \[AgN{{O}_{3}}\] as it reacts with it.
You need to login to perform this action.
You will be redirected in
3 sec
