A) \[{{S}_{1}}\]
B) \[2{{s}_{1}}\]
C) \[3{{s}_{1}}\]
D) \[4{{s}_{1}}\]
Correct Answer: C
Solution :
In 20 seconds, total distance travelled \[s=\frac{1}{2}a{{(20)}^{2}}=\frac{1}{2}a\times 400\] \[=200\,a\] In first 10 seconds, the distance Si travelled \[{{s}_{1}}=\frac{1}{2}a\times {{(10)}^{2}}\] \[=50a\] So, in other 10 seconds, the distance \[{{s}_{2}}\] travelled \[{{s}_{2}}=s-{{s}_{1}}\] or \[{{s}_{2}}=200a-50a\] or \[=150a\] or \[=3\times (50a)\] Hence, \[{{s}_{2}}=3s & 1\]
You need to login to perform this action.
You will be redirected in
3 sec
