A) \[{{f}_{0}}+{{f}_{e}}\]
B) \[{{f}_{0}}\times {{f}_{e}}\]
C) \[\frac{{{f}_{0}}}{{{f}_{e}}}\]
D) \[\frac{{{f}_{e}}}{{{f}_{0}}}\]
Correct Answer: C
Solution :
Magnifying power of telescope for relaxed eye \[M=\frac{{{f}_{0}}}{{{f}_{e}}}=\frac{{{f}_{0}}}{{{f}_{e}}}\] (numerically)You need to login to perform this action.
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