A) \[\frac{{{\mu }_{0}}i}{2r}\]
B) \[\frac{{{\mu }_{0}}i}{4r}\]
C) \[\frac{{{\mu }_{0}}i}{r}\]
D) \[\frac{{{\mu }_{0}}i}{2\pi r}\]
Correct Answer: B
Solution :
Magnetic field at centre of a circular coil, \[b=\frac{{{\mu }_{0}}Ni}{2r}\] Here \[N=\frac{1}{2}\] \[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,B=\frac{\left( \frac{1}{2} \right)i}{2r}\] \[=\frac{{{\mu }_{0}}i}{4r}\]
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