A) \[\frac{R}{2}\]
B) \[2R\]
C) \[4R\]
D) \[16R\]
Correct Answer: C
Solution :
If a same wire is stretched, its length increases but cross-sectional area decreases. When same wire is stretched, \[R\propto {{l}^{2}}\] \[\therefore \] \[\frac{R}{R}={{\left( \frac{l}{l} \right)}^{2}}\] Here: \[l=2l\] \[\therefore \] \[\frac{R}{R}={{\left( \frac{2l}{l} \right)}^{2}}=4\] \[\Rightarrow \] \[R=4R\]
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