A) \[0,0\]
B) \[0,\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{q}{R}\]
C) \[\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{q}{{{R}^{2}}}\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{q}{R}\]
D) \[\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{q}{{{R}^{2}}}0\]
Correct Answer: B
Solution :
Inside a hollow sphere,\[E=0\]and potential is same as on the surface. \[\therefore \] \[{{V}_{in}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{Q}{R}\]
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