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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2003

  • question_answer
    The electric field required to keep a water drop of mass in and charge e just to remain suspended is:

    A)  \[mg\]                                

    B)  \[emg\]

    C)  \[\frac{mg}{e}\]            

    D)         \[\frac{em}{g}\]

    Correct Answer: C

    Solution :

    For equilibrium of charged drop, upward electric force = downward weight \[eE=mg\] \[\Rightarrow \]Electric field, \[E=\frac{mg}{e}\]


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