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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2003

  • question_answer
    A point charge is located at 0. There is a point P at a distance r from it. The electric field at point P is 500 V/m and a potential of 3000 V. Then the value of r is

    A)  6m                                        

    B)  12m

    C)  24 m                    

    D)         36 m

    Correct Answer: A

    Solution :

    Electric field due to a point charge \[E=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{q}{{{r}^{2}}}\] Electric potential due to a point charge\[V=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{q}{r}\] Dividing, \[\frac{E}{V}=\frac{1}{r}\] \[\Rightarrow \]               \[r=\frac{V}{E}=\frac{3000}{500}=6\,metre\]


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