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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2003

  • question_answer
    A plane progressive wave is given by \[y=25\cos (2\pi t-\pi x)\] Then the amplitude and frequency are respectively

    A)  25, 100                

    B)         25, 1

    C)  25, 2                     

    D)         50\[\pi ,\] 2

    Correct Answer: B

    Solution :

    Given equation is \[y=25\,\cos \,(2\pi t-\pi x)\]                                      ...(1) Standard equation is     \[y=A\,\cos \,(\omega t-kx)\]                                                ...(2) Comparing (1) and (2), Amplitude\[A=25,\,\omega =2\pi ,\,k=\pi \] \[\therefore \]Frequency, \[n=\frac{\omega }{2\pi }=\frac{2\pi }{2\pi }=1Hz\]


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