RAJASTHAN PMT Rajasthan - PMT Solved Paper-2004

  • question_answer
    An ideal gas is carried along the cycle ABCA as shown in figure. The net heat given to gas in cycle is 5J. In process\[C\to A,\] the work done by the gas is:

    A)  -5J                        

    B)  -10 J

    C)  -20 J                     

    D)         -15 J

    Correct Answer: A

    Solution :

    From first law of thermodynamics \[\Delta U=Q-W\] For cycle ABCA, \[\Delta U=0\] \[\therefore \]  \[Q=W={{W}_{AB}}+{{W}_{BC}}+{{W}_{CA}}\] \[\Rightarrow \]               \[5=10+0+{{W}_{CA}}\] \[\therefore \]         \[{{W}_{CA}}=-5\,\text{J}\]


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