A) \[Ethane+C{{l}_{2}}\xrightarrow{h\omega }\]
B) \[Ethane+C{{l}_{2}}(excess)\xrightarrow{h\omega }\]
C) \[Ethane+C{{l}_{2}}\xrightarrow{in\,dark}\]
D) \[Benzene+C{{l}_{2}}\xrightarrow{{}}\]
Correct Answer: A
Solution :
Ethane and limited quantity of chlorine reacts in presence of sunlight to form ethyl chloride. Whereas in presence of excess chlorine, hexa-chloro ethane (artificial camphor) is obtained. \[{{C}_{2}}{{H}_{6}}+C{{l}_{2}}\xrightarrow{hv}{{C}_{2}}{{H}_{5}}Cl+HCl\]
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