A) \[C{{H}_{3}}-CHI-C{{H}_{3}}\]
B) \[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{3}}I\]
C) \[C{{H}_{3}}-CHI-C{{H}_{2}}I\]
D) none of the above
Correct Answer: A
Solution :
Propene adds on HI according to Markownikoffs reaction. \[C{{H}_{3}}-CH=C{{H}_{2}}+HI\xrightarrow{{}}\underset{\text{2-iodo-propane}}{\mathop{C{{H}_{3}}-\underset{I}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-C{{H}_{3}}}}\,\]
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