A) \[RCOCl>RCOOCOR>RCON{{H}_{2}}\]
B) \[RCOCl<RCOOCOR<RCON{{H}_{2}}\]
C) \[RCOCl>RCOOCOR<RCON{{H}_{2}}\]
D) none of the above
Correct Answer: A
Solution :
The correct order of reactivity of acid derivatives is: \[RCOCl>RCOOCOR>RCOOR\] \[>RCON{{H}_{2}}\] It is due to the fact that \[C{{l}^{-}}\] is the best leaving group among these being weakest base. \[C{{l}^{-}}>RCO{{O}^{-}}>R{{O}^{-}}>N{{H}_{2}}\]
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