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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2004

  • question_answer
    The time period of a vibrating spring due to a mass m is T. For twice of its mass, the new time period will be:

    A)  \[\sqrt{2}T\]                                     

    B)  \[2\sqrt{2}T\]

    C)  \[4T\]                  

    D)         \[5T\]

    Correct Answer: A

    Solution :

    The time period of spring         \[T=2\pi \sqrt{\left( \frac{m}{R} \right)}\]                                     ?(1) k = force constant of spring again \[T=2\pi \sqrt{\left( \frac{m}{k} \right)}\]             \[=2\pi \sqrt{\left( \frac{2m}{k} \right)}(\because m=2m)\]                             ?(2) From equations (1) and (2) \[\therefore \]       \[T=\sqrt{2}\,T\]        


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