A) 2 rad
B) 3 rad
C) 1 rad
D) 8 rad
Correct Answer: C
Solution :
In Fraunhofer diffraction, the angular separation of central maxima on either side is \[\text{=}\lambda \text{/e}\] So, angular width\[\text{2}\text{=2}\lambda \text{/e}\] where, e = slit width \[\therefore \] \[2\text{=}\frac{2\times 6000\times {{10}^{-10}}}{12\times {{10}^{-5}}\times {{10}^{-2}}}=1\,rad\]You need to login to perform this action.
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