A) \[S{{c}^{2-}}\]
B) \[{{S}^{2-}}\]
C) \[{{O}^{2-}}\]
D) \[T{{e}^{2-}}\]
Correct Answer: A
Solution :
Oxygen is in second period, hence atomic size will be least for \[{{O}^{2-}}\]. Due to this, charge density will be highest on \[{{O}^{2-}}\].
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