A) \[4{}^\circ \]
B) \[3{}^\circ \]
C) \[2.6{}^\circ \]
D) \[5.3{}^\circ \]
Correct Answer: B
Solution :
\[(np-1){{A}_{p}}=({{n}_{Q}}-1){{A}_{Q}}\] \[(1.54-1)4{}^\circ =(1.72-1){{A}_{Q}}\] \[\Rightarrow \] \[{{A}_{Q}}=\frac{0.54\times 4}{0.72}=3{}^\circ \]You need to login to perform this action.
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