A) \[C{{r}^{3+}}\]
B) \[M{{n}^{2+}}\]
C) \[M{{n}^{3+}}\]
D) \[N{{i}^{2+}}\]
Correct Answer: B
Solution :
\[_{24}C{{r}^{3+}}=[Ar]\,3{{d}^{3}}(n=3)\] \[_{25}M{{n}^{2+}}=[Ar]\,3{{d}^{5}}(n=5)\] \[_{25}M{{n}^{3+}}=[Ar]\,3{{d}^{4}}(n=4)\] \[_{28}N{{i}^{2+}}=[Ar]\,3{{d}^{8}}(n=3)\] \[M{{n}^{2+}}\] is the most paramagnetic as it has maximum unpaired electrons (5).
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