A) \[\frac{E}{2}\]
B) \[\frac{3}{4}E\]
C) \[\frac{9}{16}E\]
D) none of these
Correct Answer: C
Solution :
The kinetic energy of a particle executing SHM is \[E=\frac{1}{2}m\,{{\omega }^{2}}{{a}^{2}}\] where a = amplitude of particle \[\therefore \] \[\frac{E}{E}=\frac{a{{}^{2}}}{{{a}^{2}}}\] \[\Rightarrow \] \[\frac{E}{E}=\frac{{{\left( \frac{3}{4}a \right)}^{2}}}{{{a}^{2}}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\left( \therefore a=\frac{3}{4}a \right)\] \[\therefore \] \[E=\frac{9}{16}E\]
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