A) 330.5 m/sec
B) 340.5 m/sec
C) 346.5 m/sec
D) None of these
Correct Answer: C
Solution :
For first closed organ pipe \[{{n}_{1}}=\frac{\upsilon }{4{{l}_{1}}}=\frac{\upsilon }{4\times 0.75}\] For second closed organ pipe \[{{n}_{2}}=\frac{\upsilon }{4{{l}_{2}}}=\frac{\upsilon }{4\times 0.77}\] B \[{{n}_{1}}-{{n}_{2}}=3\] \[\frac{\upsilon }{4\times 0.75}\times \frac{\upsilon }{4\times 0.77}=3\] \[\frac{\upsilon }{3}-\frac{\upsilon }{3.08}=3\] \[\upsilon \left( \frac{3.08=3}{3\times 3.08} \right)=3\] \[\Rightarrow \] \[\upsilon =\frac{3\times 3\times 3.08}{0.08}=346.5\,m/\sec \]
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